1,25x^2-10x=0

Solution for 1,25x^2-10x=0 equation:

1.25x^2-10x=0

a = 1.25; b = -10; c = 0;
Δ = b2-4ac
Δ = -102-4·1.25·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10}{2*1.25}=\frac{0}{2.5}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10}{2*1.25}=\frac{20}{2.5}
=8
$